The triangles ABC and ADE are similar.

Which of the following is true ?

\frac{A B}{A D} = \frac{B C}{D E}

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\frac{B C}{B D} = \frac{C E}{D E}

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$\frac{E C}{A C} = \frac{A D}{D E}$

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All of the above.

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Solution

The correct option is A $\frac{A B}{A D} = \frac{B C}{D E}$
Since the given triangles are similar, the ratios of corresponding sides are equal.

So, $\frac{A B}{A D} = \frac{B C}{D E} = \frac{A C}{A E}$

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Similar questions

The triangles ABC and ADE are similar.

Which of the following is true ?

If the triangles ABC and ADE are similar, then $\frac{A B}{A D}$ =.

If AD is external bisector of $∠ A$ which meets BC at D and CE || DA. Then, which of the following is true?

△ A B C, A B = B C, A D ⊥ B C, C E ⊥ A B .

A D = C E

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