Question

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m, 15 m. The advertisements yield an earning of Rs 2000 per $m^2$ a year. A company hired one of its walls for 6 months. How much rent did it pay ?

Answer 1

GIVEN:-
a=13m
b=14m
c=15m
SEMI-PERIMETER OF THE TRIANGLE, s = $\frac{13+14+15}{2}$ = 21m
USING HERON'S FORMULA,
AREA=$\sqrt{s(s-a)(s-b)(s-c)}$
=$\sqrt{21(21-13)(21-14)(21-15)}$
=$\sqrt{21\times 8\times 7\times 6}$
=√7056
AREA = 84 $m^2$
since,1 $m^2$ costs Rs.2000 per year
therefore, 84 $m^2$ will cost 2000 x 84,that is Rs168000 per year
therefore for 6 months,i.e. 0.5 year,it will cost
=168000 x 0.5
=Rs.84000
THUS,THE COMPANY WILL HAVE TO PAY Rs.84000 AS RENT.