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Question

The trigonometric ratio equivalent to the following is:

sin55+cos20+cot70+cosec85


A

cos35+sin20+tan20+sec5

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B

cos35+sin70+tan20+sec5

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C

cos35+sin20+tan70+sec5

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D

cos35+sin20+tan70+sec85

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Solution

The correct option is B

cos35+sin70+tan20+sec5


Since,

sinA=cos(90A)

cosA=sin(90A)

cosecA=sec(90A)

cotA=tan(90A)

Hence,sin55+cos20+cot70+cosec85=cos(9035)+sin(9070)+tan(9020)+sec(905)=cos35+sin70+tan20+sec5


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