Question

The triple point of carbon dioxide is 216.55K. Express this temperature on Fahrenheit scale

Answer 1

$$\begin{gathered} \mathbf{Relation}\mathbf{}\mathbf{between}\mathbf{}\mathbf{Vahrenheit}\mathbf{}\mathbf{scale}\mathbf{}\mathbf{and}\mathbf{}\mathbf{kelvin}\mathbf{}\mathbf{scale}\mathbf{:} \\ \frac{\mathrm{F}-32}{180}=\frac{\mathrm{K}-273.15}{100} \\ \mathrm{F}=32+\left(\frac{180}{100}\right)\left(\mathrm{K}-273.15\right) \\ =32+\left(\frac{180}{100}\right)\left(216.55-273.15\right) \\ \mathbf{=}\mathbf{-}\mathbf{69}\mathbf{.}{\mathbf{88}}^{\mathbf{o}}\mathbf{F} \end{gathered}$$