The true discount on a bill of Rs. 540 is Rs. 90. The banker's discount is :

Rs. 60

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Rs. 108

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Rs. 110

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Rs. 112

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Solution

The correct option is B Rs. 108
P.W. = Rs. (540-90) = Rs. 450
Therefore, SI on Rs. 450 = Rs. 90
SI on Rs. 540 = Rs. $\frac{90 \times 540}{450} = R s . 108$
Therefore, banker's discount = Rs. 108

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The true discount on a bill of Rs. 540 is Rs. 90. The banker's discount is :

The correct option is B Rs. 108P.W. = Rs. (540-90) = Rs. 450Therefore, SI on Rs. 450 = Rs. 90SI on Rs. 540 = Rs. 90×540450=Rs.108Therefore, banker's discount = Rs. 108

The correct option is B Rs. 108
P.W. = Rs. (540-90) = Rs. 450
Therefore, SI on Rs. 450 = Rs. 90
SI on Rs. 540 = Rs. $\frac{90 \times 540}{450} = R s . 108$
Therefore, banker's discount = Rs. 108