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Byju's Answer
Standard VIII
Mathematics
Difference of Two Sets
The true set ...
Question
The true set of real values of
x
for which the function,
f
(
x
)
=
x
ln
x
(
x
+
1
)
is positive is:
A
(
0
,
∞
)
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B
(
1
e
,
∞
)
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C
[
e
,
∞
)
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D
(
0
,
1
)
∪
(
1
,
∞
)
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Solution
The correct option is
A
(
0
,
∞
)
f
(
x
)
=
x
ln
x
(
x
+
1
)
f
(
x
)
=
>
0
means
x
>
0
Hence
l
n
(
x
+
1
)
x
>
0
which is only positive when
x
(
x
+
1
)
>
0
hence
x
ϵ
(
−
∞
,
−
1
)
∪
(
0
,
∞
)
but
x
>
0
Hence
x
ϵ
(
0
,
∞
)
.
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0
Similar questions
Q.
The true set of real value of
x
for which the function,
f
(
x
)
=
x
l
n
x
−
x
+
1
is positive is
Q.
Which one of the following sets is true set of real values of x for which the function,
f
(
x
)
=
x
ℓ
n
x
−
x
+
1
positive ?
Q.
Let f:
[
0
,
1
]
→
R
(the set of all real numbers) be a function. Suppose the function f is twice differentiable,
f
(
0
)
=
f
(
1
)
=
0
and satisfies
f
′′
(
x
)
−
2
f
′
(
x
)
+
f
(
x
)
≥
e
x
,
x
∈
[
0
,
1
]
If the function
e
−
x
f
(
x
)
assumes its minimum in the interval [0, 1] at
=
1
4
, which of the following is true?
Q.
Let
f
:
[
0
,
1
]
→
R
(the set of all real numbers) be a function. Suppose the function
f
is twice differentiable,
f
(
0
)
=
f
(
1
)
=
0
and satisfies
f
′′
(
x
)
−
2
f
′
(
x
)
+
f
(
x
)
≥
e
x
,
x
∈
[
0
,
1
]
Which of the following is true for
0
<
x
<
1
?
Q.
Let f:
[
0
,
1
]
→
R
(the set of all real numbers) be a function. Suppose the function f is twice differentiable,
f
(
0
)
=
f
(
1
)
=
0
and satisfies
f
"
(
x
)
−
2
f
′
(
x
)
+
f
(
x
)
≥
e
x
,
x
∈
[
0
,
1
]
Which of the following is true for
0
<
x
<
1
?
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