The true stress-true strain curve is given by - -1500 -0-45- where the stress - is in MPa- The mean flow stress at the maximum load in MPa is

Strain hardening equation is given by nbsp; nbsp; nbsp; σ =kε^n At maximum load, σ = ultimate stress ∴ true strain, ε =n=0.45 ⇒ σ_u=1500×0.45^0.45=104 ...

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The true stress-true strain curve is given by $σ = 1500 ε^{0.45},$ where the stress $σ$ is in MPa. The mean flow stress at the maximum load (in MPa) is

1047

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427

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722

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397

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Solution

The correct option is C 722
Strain hardening equation is given by
$σ = k ε^{n}$
At maximum load, $σ$ = ultimate stress
$∴$ true strain, $ε = n = 0.45$

$\Rightarrow σ_{u} = 1500 \times {0.45}^{0.45} = 1047.27 M P a$
Mean flow stress,

$σ_{m f} = \frac{σ_{u}}{n + 1} = \frac{1047.27}{0.45 + 1} = 722.21 M P a$

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The true stress-true strain curve is given by σ=1500ε0.45, where the stress σ is in MPa. The mean flow stress at the maximum load (in MPa) is

The correct option is C 722Strain hardening equation is given by σ=kεn At maximum load, σ = ultimate stress ∴ true strain, ε=n=0.45 ⇒σu=1500×0.450.45=1047.27MPa Mean flow stress, σmf=σun+1=1047.270.45+1=722.21MPa

The true stress-true strain curve is given by $σ = 1500 ε^{0.45},$ where the stress $σ$ is in MPa. The mean flow stress at the maximum load (in MPa) is