Question

The turn on a banked road has a radius of $25m$. If the coefficient of friction between a car tyre and the road surface is $0.32$ and if the angle of banking is ${17}^o$, what is the maximum velocity at which a car can turn? (in m/s)

• A. $12.6$
  
• B. $18.6$
  
• C. $13.04$
  
• D. $14.3$
  

Answer 1

The correct option is C $13.04$

$v=\sqrt{\frac{rg(\mu +tan\theta )}{1+\mu \tan \theta }}$

$v=\sqrt{\frac{25\ast 9.8(0.32+tan{17}^0)}{1+0.32\ast \tan {17}^0}}$

$v=13.04m/s$