Question

The turn ratio of a transformer is given as 2:3. If the current through the primary coil is 6 A , calculate the current through secondary coil.

• A.
  9 A
• B.
  6 A
• C.
  4 A
• D. 2 A

Answer 1

The correct option is C

4 A
Given:
Turn ratio of the transformer = 2:3
Current through primary coil = 6 A

We know that:
$a=\frac{N_P}{N_S}=\frac{V_P}{V_S}=\frac{I_S}{I_P}Here,a=Turnratioofthetransformer{N}_P=Numberofturnsinprimarycoil{N}_S=Numberofturnsinsecondarycoil{V}_P=Primaryvoltage{V}_S=Secondaryvoltage{I}_P=Primarycurrent{I}_S=Secondarycurrent$
So,
$a=\frac{N_P}{N_S}=\frac{2}{3}and{I}_P=6A$

$a=\frac{N_P}{N_S}=\frac{I_S}{I_P}\Rightarrow \frac{2}{3}=\frac{I_S}{6}\Rightarrow I_S=\frac{12}{3}=4\Rightarrow I_S=4A$
Thus, the current through the secondary coil is 4 A.