The two adjacent sides of a rectangle are 3a -b and 6b-a find its perimeter?

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Solution

$Given that two adjacent sides of a rectangle are 3 a - b and 6 b - a Let length of rectangle = 3 a - b And, breadth of rectangle = 6 b - a Perimeter of rectangle = 2 (length of rectangle + breadth of rectangle) \Rightarrow Perimeter of rectangle = 2 (3 a - b + 6 b - a) \Rightarrow Perimeter of rectangle = 2 (2 a + 5 b) \Rightarrow Perimeter of rectangle = 4 a + 10 b$

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Two adjacent sides of a rectangle are $5 x^{2} - 3 y^{2}$ and $x^{2} - 2 x y$ . Find its perimeter. [3 MARKS]

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