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Relative Velocity in 2D

the two balls...

Question

the two balls will collide at time $t =$

2 s

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5 s

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10 s

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3 s

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Solution

The correct option is A $2 s$
$\Rightarrow y = \frac{1}{2} g t^{2} \to (1)$
$\Rightarrow 35 + y = 10 (t + 1) + \frac{1}{2} g {(t + 1)}^{2}$
Put $g$ from $(1)$
$\Rightarrow 35 + \frac{1}{2} g t^{2} = 10 + 10 + \frac{1}{2} g t^{2} + g t + \frac{g}{2}$
$\Rightarrow 20 = 20 t$
$t = 1 s e c$
$\Rightarrow t + 1 = 2 s e c$
The two ball will collects at time $2$ seconds.
Hence, the answer is $2 s .$

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the two balls will collide at time t=

The correct option is A 2s⇒y=12gt2→(1)⇒35+y=10(t+1)+12g(t+1)2Put g from (1)⇒35+12gt2=10+10+12gt2+gt+g2⇒20=20t t=1sec⇒t+1=2secThe two ball will collects at time 2seconds.Hence, the answer is 2s.

the two balls will collide at time $t =$