The two blocks $m = 10 k g$ are free to move as shown. The coefficient of static friction between the blocks is $0.5$ and there is no friction between $M$ and the ground. A minimum horizontal force $F$ is applied to hold in against $M$ that is equal to

100 N

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50 N

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240 N

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180 N

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Solution

The correct option is A $100 N$
$\begin{matrix} F = (M + m) a = 20 a N = 10 a N = μ m g = 100 \times \frac{5}{10} = 50 \Rightarrow 50 = 10 a \Rightarrow a = 5 ∴ F = 100 N H e n c e, o p t i o n A i s c o r r e c t a n s w e r . \end{matrix}$

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