The two electrical subnetworks N1 and N2 are connected through three resistors as shown in Fig. The voltages across 5 ohm resistor and 1 ohm resistor are given to be 10 V and 5 V, respectively. Then voltage across 15 ohm resistor is
A
-105 V
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B
+105 V
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C
-15 V
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D
+15 V
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Solution
The correct option is A -105 V Current through 5Ω resistor, i5=105=2 Amp.
Current through 1Ω resistor, i1=51=5 Amp.
So, the current through 15Ω resistor, i15=−(i1+i5)=−(5+2)=−7 Amp.
Voltage across 15Ω resistor. V15=15(i15)=15(−7)=−105V