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Question

The two ends of a train moving with uniform acceleration pass a certain point with velocities 6 kmph and 8 kmph respectively. What is the velocity with which the middle point of the train passes the same point?

A
7 kmph
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B
52 kmph
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C
210 kmph
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D
7.5 kmph
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Solution

The correct option is B 52 kmph
The rear point which had initially a velocity of 6 kmph attained a velocity of 8 kmph after having a displacement of the length of the train's

Using
v2u2=2as

as=(8262)2=14


The middle point which had initially a velocity of 6 kmph will acquire a velocity V after moving through a distance equal to half the length of the train =(s/2)

V2=u2+2a(s/2)
V2=u2+as
V2=62+14
V2=50

V=52kmph

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