Question

The two ends of a train moving with uniform acceleration passes a certain point with velocities 36kmph and 72kmph. What is the velocity with which the middle point of the train passes the same point?

Answer 1

We all know that,
v²-u²=2as or v²=u²+2as -----> (1)
a=v²-u²/2s
Now for the mid-point of the train
s¹=s/2
a₁=v₁²-u²/2s¹
a₁=v₁²-u²/2s/2
a₁=v₁²-u²/s or v₁²=u² + as ----> (2)
from (1) and (2) you will get
as= v²-u²/2
v₁²=u² + as
v₁²= v²+u² /2
put u =36 and v = 72