The two forces as shown in above figure are 6 N and 4 N and acting in opposite directions. The mass of the object is 2 kg. What is the acceleration of the mass?

4 m/s²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 m/s²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 m/s²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 m/s²

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
1 m/s²

We know that, $F_{n e t}$ = m $\times$ a

Mass of the object is 2 kg and net force is (6 N – 4 N) = 2 N

Thus, the acceleration,
$a = \frac{F}{m} = \frac{2}{2} = 1 m / s^{2}$

Suggest Corrections

Similar questions

If two forces as shown in above figure are 6 N and 4N are acting opposite. The mass of the object is 2kg. What is the acceleration of the mass?

If two forces 6 N and 4 N are acting on the body as shown in the figure. The mass of the object is 2kg. What is the acceleration of the object?

Consider two forces 6 N and 4 N as shown in below figure acting on an object in the opposite directions. The mass of the object is 2 kg. What is the acceleration of the object?

Q. Find the normal force and acceleration respectively of the

2 kg

block shown in the figure.

(Take g = 10 {m/s}^{2})

Q. What is the acceleration of

3 kg

mass when acceleration of

2 kg

mass is

2 {m/s}^{2}

as shown ?

Join BYJU'S Learning Program

The two forces as shown in above figure are 6 N and 4 N and acting in opposite directions. The mass of the object is 2 kg. What is the acceleration of the mass?

The correct option is D 1 m/s2 We know that, Fnet ​ = m × a Mass of the object is 2 kg and net force is (6 N – 4 N) = 2 N Thus, the acceleration, a=Fm=22=1 m/s2

The correct option is D
1 m/s²

We know that, $F_{n e t}$ = m $\times$ a

Mass of the object is 2 kg and net force is (6 N – 4 N) = 2 N

Thus, the acceleration,
$a = \frac{F}{m} = \frac{2}{2} = 1 m / s^{2}$