The two geometric means between the numbers 1 and 64 are
4 and 16
(b) 4 and 16
Let the two G.M. s between 1 and 64 and G1 and G2.
Thus, 1,G1,G2 and 64 are in G.P.
64=1×r3
⇒r=3√64
⇒r=4
⇒G1=ar=1×4=4
And G2=ar2=1×42=16
Thus, 4 and 16 are the required G.M.s.