Question

The two line segment joining $(-2,7),(-5,-3)$ and $(-8,-13),(1,17)$ cut each other at

• A. Infinitely many points
• B. No point
• C. Only one point
• D. None of these

Answer 1

The correct option is A Infinitely many points

$A(-2,7)B(-5,-3)$

$AB:y-7=\frac{-3-7}{-5+2}(x+2)$

$y-7=\frac{+10}{+3}(x+2)$

$3y-21=10x+20$

$3y-10x-41=0$

$c(-8,-13)D(1,17)$

$CD:y+13=\frac{17+13}{1+8}(x+8)$

$(y+13)=\frac{30}{9}(x+8)$

$3y+39=10x+80$

$3y-10x-41=0$

$\because$ both are coinciding.

$\therefore$ cut at infinity many points.