The two monomers for the synthesis of Nylon $6$ , $6$ are:

H O O C (C H_{2})_{6} C O O H, H_{2} N (C H_{2})_{6} N H_{2}

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H O O C (C H_{2})_{4} C O O H, H_{2} N (C H_{2})_{4} N H_{2}

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H O O C (C H_{2})_{6} C O O H, H_{2} N (C H_{2})_{4} N H_{2}

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H O O C (C H_{2})_{4} C O O H, H_{2} N (C H_{2})_{6} N H_{2}

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Solution

The correct option is D $H O O C (C H_{2})_{4} C O O H, H_{2} N (C H_{2})_{6} N H_{2}$
$Nylon 66$ is made of two monomers each containing 6 carbon atoms, hexamethylenediamine and adipic acid, which give nylon 66 its name.

$Hexamethylene diamine ↓ H_{2} N - (C H_{2})_{6} - N H_{2}$ + $Adipic acid ↓ H O O C - (C H_{2})_{4} - C O O H$ .

Hence, option D is correct.

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