Question

The two monomers for the synthesis of Nylon $6$, $6$ are:

• A. $HOOC(C{H}_2{)}_{6}COOH,H_{2}N(C{H}_2{)}_{6}N{H}_2$
• B. $HOOC(C{H}_2{)}_{4}COOH,H_{2}N(C{H}_2{)}_{4}N{H}_2$
• C. $HOOC(C{H}_2{)}_{6}COOH,H_{2}N(C{H}_2{)}_{4}N{H}_2$
• D. $HOOC(C{H}_2{)}_{4}COOH,H_{2}N(C{H}_2{)}_{6}N{H}_2$

Answer 1

The correct option is D $HOOC(C{H}_2{)}_{4}COOH,H_{2}N(C{H}_2{)}_{6}N{H}_2$

$\text{Nylon}66$ is made of two monomers each containing 6 carbon atoms, hexamethylenediamine and adipic acid, which give nylon 66 its name.

$\underset{\underset{H_{2}N-(C{H}_2{)}_6-N{H}_2}{\downarrow }}{\text{Hexamethylene diamine}}$ + $\underset{\underset{HOOC-(C{H}_2{)}_4-COOH}{\downarrow }}{\text{Adipic acid}}$.

Hence, option D is correct.