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Conduction Law

The two oppos...

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The two opposite faces of a cubical piece of iron (thermal conductivity = 0.2 CGS units) are at 100 °C and 0 °C in ice. If the area of a surface is 4 cm2, then the mass of ice melted in 10 minutes will be

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Q. The two opposite faces of a cubical piece of iron (thermal conductivity = 0.2 CGS units) are at

100^{\circ}

0^{\circ}

C in ice. If the area of a surface is

4 c m^{2}

, then the mass of ice melted in 10 minutes will be

Q. The two opposite faces of a cubical piece of iron (thermal conductivity = 0.2 CGS units) are at

100^{\circ}

0^{\circ}

C in ice. If the area of a surface is

4 c m^{2}

, then the mass of ice melted in 10 minutes will be

Q. The two opposite faces of a cubical piece of iron (thermal conductivity

= 0.2 CGS units

100^{\circ} C

0^{\circ} C

in contact with ice. If the area of a surface is

4 {cm}^{2}

and latent heat of fusion of ice is

80 J/g

, then the mass of ice melted in

10

minutes will be

Q. The two opposite faces of a cubical piece of iron (thermal conductivity

= 0.2 CGS units

100^{\circ} C

0^{\circ} C

0^{\circ} C

is in contact with the ice at

0^{\circ} C

. If the area of a surface is

4 {cm}^{2}

and latent heat of fusion of ice is

80 J/g

, then the mass of ice melted in

10

minutes will be:

Q. The opposite faces of a cubic block of iron of cross-section area

4 c m^{2}

are kept in contact with steam and melting ice. The quantity of ice melting at the end of

10

min will be :
(Given:

K_{i r o n}

= 0.2

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