Question

The two regression lines are $3x+12y=19$ and $9x+3y=46$. Find $b_{yx}$

• A. $\frac{-1}{4}$
• B. $\frac{1}{10}$
• C. $\frac{-1}{30}$
• D. $\frac{9}{20}$

Answer 1

Answer: (A), (D)

The correct options are
A $\frac{-1}{4}$
D $\frac{9}{20}$

$=3x-12y=19$

$\Rightarrow y=\frac{19}{12}-\frac{3}{12}x$

so, $\Rightarrow b_{yx}=\frac{-3}{12}=\frac{-1}{4}$