The two sets L-k-k- k2-2-7 -M-m-m- 1-m-3 are

Given sets: nbsp;L={k:k∈𝕀, k^2 2=7} and nbsp;M={m:m∈ℕ, 1 lt;m lt;3} Here, let's solve the expression k^2 2=7 ⇒ k^2=9 ⇒ k=+√(9) or k= √(9) ⇒ k=3 or k= 3 ...

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Byju's Answer

Standard XII

Mathematics

Equal, Equivalent and Unequal Sets

The two sets ...

Question

The two sets $L = {k : k \in I, k^{2} - 2 = 7} &$
$M = {m : m \in N, 1 < m < 3}$ are

Equal Sets

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Equivalent but not equal sets

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Unequal sets

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Solution

The correct option is C Unequal sets
Given sets: $L = {k : k \in I, k^{2} - 2 = 7}$ and $M = {m : m \in N, 1 < m < 3}$
Here, let's solve the expression $k^{2} - 2 = 7$
$\Rightarrow k^{2} = 9$
$\Rightarrow k = + \sqrt{9} or k = - \sqrt{9}$
$\Rightarrow k = 3 or k = - 3$
$\Rightarrow L = {- 3, 3}$

Similarly, we can write $M$ in roster form as:
$M = {2}$
$\Rightarrow L and M$ are unequal sets.

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Similar questions

Q. Two electrons have the following sets of quantum numbers:

X : n = 3, l = 2, m = - 2, s = + \frac{1}{2}

Y : n = 3, l = 1, m = - 1 s = + \frac{1}{2}

Which of the following is true?

Q. Consider the following sets of quantum numbers.

(i) n - 3, l - 0, m - 0, s - +1/2

(ii) n - 2, l - 2, m - 1, s - +1/2

(iii) n - 4, l - 3, m - 2, s -1/2

(iv) n - 1, l - 0, m - 1, s -1/2

(v) n - 3, l - 2, m - 3, s - +1/2

Which of the following sets of quantum numbers is not possible?

Q. From the following sets of quantum number, sets which are possible?

(i) n = 1 l = 0 m = 0 s = + \frac{1}{2} (i i) n = 3 l = 1 m = 0 s = - \frac{1}{2} (i i i) n = 2 l = 1 m = + 2 s = + \frac{1}{2} (i v) n = 3 l = 2 m = + 2 s = - \frac{1}{2} (v) n = 3 l = 3 m = + 1 s = + \frac{1}{2}

Explain, giving reasons, which of the following sets of quantum numbers are not possible.
a) n = 0 l = 0 ml = 0 $m, = + \frac{1}{2}$
b) n = 1 l = 0 ml = 0 $m, = - \frac{1}{2}$
c) n = 1 l = 1 ml = 0 $m, = + \frac{1}{2}$
d) n = 2 l = 1 ml = 0 $m, = - \frac{1}{2}$
e) n = 3 l = 3 ml = – 3 $m, = + \frac{1}{2}$
f) n = 3 l = 1 ml = 0 $m, = + \frac{1}{2}$

Q. Arrange the electrons represented by the following sets of quantum numbers in decreasing order of energy.
(i)

n = 4, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}

(ii)

n = 3, l = 1, m_{l} = 1, m_{s} = - \frac{1}{2}

(iii)

n = 3, l = 2, m_{l} = 0, m_{s} = + \frac{1}{2}

(iv)

n = 3, l = 0, m_{l} = 0, m_{s} = - \frac{1}{2}

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The two sets L={k:k∈I,k2−2=7} & M={m:m∈N,1<m<3} are

The correct option is C Unequal setsGiven sets: L={k:k∈I,k2−2=7} and M={m:m∈N,1<m<3} Here, let's solve the expression k2−2=7 ⇒k2=9 ⇒k=+√9 or k=−√9 ⇒k=3 or k=−3 ⇒L={−3,3} Similarly, we can write M in roster form as: M={2} ⇒L and M are unequal sets.

The two sets $L = {k : k \in I, k^{2} - 2 = 7} &$
$M = {m : m \in N, 1 < m < 3}$ are