The type of hybrid orbitals used by chlorine atom in $C l O^{-}, C l O_{2}^{-}, C l O_{3}^{-}$ and $C l O_{4}^{-}$ is/are:

s p, s p^{2}, s p^{3}

and

s p^{3} d

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s p

and

s p

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only

s p^{3}

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only

s p

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Solution

The correct option is C only $s p^{3}$
The type of hybrid orbitals used by chlorine atom in $C l O^{-}, C l O_{2}^{-}, C l O_{3}^{-}$ and $C l O_{4}^{-}$ are only $s p^{3}$ . In all these ions, the sum of the lone pairs of electrons and bonding domains on $C l$ atom is $4$ . This results in $s p^{3}$ hybridization and tetrahedral geometry.

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Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

(C_{3} H_{4})

N O_{2}^{+}, N O_{3}^{-}

N H_{4}^{+}

The type of hybrid orbitals used by the chlorine atom in $C l O_{2}^{-}$ is

s p, s p^{2} a n d s p^{3}

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