The type of hybridisation present in chlorine atom of $C l O_{2}^{-}$ ion is:

s p

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{s p}^{2}

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{s p}^{3}

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d {s p}^{2}

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Solution

The correct option is B ${s p}^{3}$
The type of hybridisation present in chlorine atom of $C l O_{2}^{-}$ ion is $s p^{3}$ .
The central chlorine atom has 2 lone pairs of electrons and 2 bonding domains (one single bond and one double bond). This requires four hybrid orbitals which are obtained from $s p^{3}$ hybridisation.

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The type of hybridisation of boron in diborane is

(a) sp (b) sp²(c) sp³ (d) dsp²

The correct order of hybridisation of the central atom in the following species $N H_{3}$ , ${[P t C l_{4}]}^{2 -}$ , $P C l_{5}$ and $B C l_{3}$

N O_{3}^{-}, N O_{2}^{+} a n d N H_{4}^{+}

N O_{3}^{-}, N O_{2}^{+}, N H_{4}^{+}

C 3 - C 4

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