Question

The type of hybridization in $S{F}_6$ molecule is:

• A. $s{p}^{3}d$
• B. $ds{p}^3$
• C. $s{p}^3{d}^2$
• D. $d^{2}s{p}^3$

Answer 1

Answer: (C)

$s{p}^3{d}^2$

Electronic configuration of sulphur in ground state $\left[Ne\right]3s^{2}3p^{4}3d^0$

Electronic configuration of sulphur in excited state $\left[Ne\right]3s^{1}3p^{3}3d^2$

It has $s{p}^3{d}^2$ hybridisation due to presence of vacant d orbitals.