Question

The type of hybridization on the five carbon atoms from left to right in the molecule $C{H}_3-CH=C=CH-C{H}_3$ are:

• A. $s{p}^3,s{p}^2,s{p}^2,s{p}^2,s{p}^3$
• B. $s{p}^3,sp,s{p}^2,s{p}^2,s{p}^3$
• C. $s{p}^3,s{p}^2,sp,s{p}^2,s{p}^3$
• D. $s{p}^3,s{p}^2,s{p}^2,sp,s{p}^3$

Answer 1

The correct option is C $s{p}^3,s{p}^2,sp,s{p}^2,s{p}^3$

Hence, the type of hybridization from left to right is,

$s{p}^3,s{p}^2,sp,s{p}^2,s{p}^3$