Question

The type of isomerism exhibited by the compound with formula $C_4{H}_{10}O$ is

• A. Chain and position
• B. Functional and position
• C. Metamerism
• D. Chain, position, functional, and metamerism.

Answer 1

The correct option is

B

Chain, position, functional, and metamerism.

D.U. in $C_4{H}_{10}O=\frac{(2n_C+2)-n_H}{2}=\frac{10-10}{2}=0$ it should be alcohol or ether.
i) Alcohols and ethers are functional isomers.
ii) Alcohol shows position and chain isomerism.
iii) Ether shows position isomerism and metamerism.
So the compound $\left(C_4{H}_{10}O\right)$ shows chain, position, functional isomerisms, and metamerism.

It shows functional isomerism by forming either alcohol or aldehyde or ketone.