The types of hybridisation on the five carbon atoms from left to right in the molecule
$C H_{3} - C H = C = C H - C H_{3}$ are :

$s p^{3}, s p^{2}, s p^{2}, s p^{2}, s p^{3}$

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$s p^{3}, s p, s p^{2}, s p^{2}, s p^{3}$

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$s p^{3}, s p^{2}, s p, s p^{2}, s p^{3}$

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$s p^{3}, s p^{2}, s p^{2}, s p, s p^{3}$

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Solution

The correct option is C
$s p^{3}, s p^{2}, s p, s p^{2}, s p^{3}$

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Similar questions

Q. The type of hybridization on the five carbon atoms from left to right in the molecule

C H_{3} - C H = C = C H - C H_{3}

are:

Q. The structural formula of a compound is

C H_{3} - C H = C = C H_{2} .

The type of hybridisation at the four carbons from left to right are:

Q. The structural formula of a compound is

{C H}_{3} - C H = C = {C H}_{2}

. The type of hybridization at the four carbon atoms from left to right is:

A straight chain hydrocarbon has the molecular formula C8H10. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be

What are hybridisation states of each carbon atom in the following compounds?

$C H_{2} = C = O$

$C H_{3} C H = C H_{2}$

$(C H_{3})_{2} C O$

$C H_{2} = C H C N$ ,

$C_{6} H_{6}$

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The types of hybridisation on the five carbon atoms from left to right in the molecule CH3−CH=C=CH−CH3 are :

The correct option is C sp3,sp2,sp,sp2,sp3

The types of hybridisation on the five carbon atoms from left to right in the molecule
$C H_{3} - C H = C = C H - C H_{3}$ are :

The correct option is C
$s p^{3}, s p^{2}, s p, s p^{2}, s p^{3}$