The types of hybridisation on the five carbon atoms from left to right in the molecule
$C H_{3} - C H = C = C H - C H_{3}$ are :

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s p^{3}, s p^{2}, s p, s p^{2}, s p^{3}

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s p^{3}, s p^{2}, s p^{2}, s p^{2}, s p^{3}

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s p^{3}, s p^{2}, s p^{2}, s p, s p^{3}

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s p^{3}, s p, s p^{2}, s p^{2}, s p^{3}

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Solution

The correct option is A $s p^{3}, s p^{2}, s p, s p^{2}, s p^{3}$

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Similar questions

What are hybridisation states of each carbon atom in the following compounds?

$C H_{2} = C = O$

$C H_{3} C H = C H_{2}$

$(C H_{3})_{2} C O$

$C H_{2} = C H C N$ ,

$C_{6} H_{6}$

What are hybridisation states of each carbon atom in the following compounds?

CH₂=C=O, CH₃CH=CH₂, (CH₃)₂CO, CH₂=CHCN, C₆H₆

C H_{3} - C H = C = C H - C H_{3}

C H_{3} - C H = C = C H - C H_{3}

C H_{3} - C H = C = C H_{2} .

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