The $u_{r m s}$ speed of $O_{2}$ molecules at a certain temperature T is u. If the temperature is doubled so that $O_{2}$ dissociates into O atoms, then $u_{r m s}$ of oxygen atoms is_________.

u_{r m s} O_{2} = u_{r m s} O

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u_{r m s} O_{2} = 2 \times u_{r m s} O

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u_{r m s} O_{2} = \frac{1}{2} u_{r m s} O

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u_{r m s} O_{2} = \frac{1}{3} u_{r m s} O

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Solution

The correct option is B $u_{r m s} O_{2} = \frac{1}{2} u_{r m s} O$
As we know,
$u_{r m s} = \sqrt{3 R T / M}$ so
$U_{r m s} O_{2} = \sqrt{\frac{3 R T}{32}}$ and
$U_{r m s} O = \sqrt{\frac{3 R T \times 2}{16}}$ as T is doubled
$U_{r m s} O_{2} = U_{r m s} O \times \frac{1}{2}$

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