The ultrasonic waves from a bat hit a mosquito flying at a distance 'x' and come back to the bat after 1.8s. If the speed of the sound is 336ms−1, calculate the distance 'x' of the prey.
A
151.2m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
201.6m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
604.8m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
302.4m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D302.4m Given: Total time t=1.8s. Speed of the sound v=336ms−1. Here t is the total time taken for the sound to hit the target and come back to the source. The distance ′x′ of the target from the source is half of the total distance travelled by the sound wave which is ′2x′. Distance x is given by x=v×t2 Substituting values: x=v×t2=336×1.82 = 604.82=302.4m Therefore, the distance of mosquito from the bat is 302.4m.