The unbalanced chemical reactions given in List - I show missing reagent or condition - which are provided in List - II- Match List - I with List - II and select the correct answer using the code given below the lists- beginarray - hline List-I-List-IIN-hlineP PbO - 2- H - 2 SO - 4 xrightarrow -1 - NOPbSO4-O2-other product- IllhlineNaHSO4-other product- -llhlineN2-other product- illihlineS XeF2 xrightarrow - Xe -4 - Cl - 2 -other product- -lilhline lendarray A- P - 4- Q - 2- R - 3- S - 1B- P - 3- Q - 2- R - 1- S - 4C- P-3- Q-4- R-2- S-1D- P-1- Q-4- R-2- S-3

The correct option is C P:3, Q:4, R:2, S:1(P) PbO_2 + H_2SO_4 PbSO_4 +O_2 +2H_2O Other product = 2H_2O ? = Δ (Q) Na_2 S_2O_3 + 5H_2O 2NaHSO_4 + 8 HCI Othe ...

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Standard X

Chemistry

Sulphuric Acid

The unbalance...

Question

The unbalanced chemical reactions given in List - I show missing reagent or condition (?) which are provided in List - II. Match List - I with List - II and select the correct answer using the code given below the lists:
$\begin{matrix} L i s t - I & L i s t - I I (P) P b O_{2} + H_{2} S O_{4} ? \to & (1) N O P b S O_{4} + O_{2} + o t h e r p r o d u c t (Q) N a_{2} S_{2} O_{3} + H_{2} O ? \to & (2) I_{2} N a H S O_{4} + o t h e r p r o d u c t (R) N_{2} H_{4} ? \to & (3) W a r m N_{2} + o t h e r p r o d u c t (S) X e F_{2} ? \to X e & (4) C l_{2} + o t h e r p r o d u c t \end{matrix}$

P:4, Q:2, R:3, S:1

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P:3, Q:2, R:1, S:4

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P:1, Q:4, R:2, S:3

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P:3, Q:4, R:2, S:1

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Solution

The correct option is D P:3, Q:4, R:2, S:1
(P) $P b O_{2} + H_{2} S O_{4} Δ - \to P b S O_{4} + O_{2} + 2 H_{2} O$
Other product = $2 H_{2} O$ ? = $Δ$
(Q) $N a_{2} S_{2} O_{3} + 5 H_{2} O 4 C l_{2} - - \to 2 N a H S O_{4} + 8 H C I$
Other product = 8 HCl
? = $C l_{2}$
(R) $N_{2} H_{4} + 2 l_{2} \to N_{2} + 4 H I$
? = $I_{2}$
(S) $X e F_{2} + N O \to X e + N O F$
Other Product = NOF
? = NO
Hence answer is (D)

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Similar questions

Q. The unbalanced chemical reactions given in List - I show missing reagent or condition (?) which are provided in List - II. Match List - I with List - II and select the correct answer using the code given below the lists:

\begin{matrix} L i s t - I & L i s t - I I (P) P b O_{2} + H_{2} S O_{4} ? \to & (1) N O P b S O_{4} + O_{2} + o t h e r p r o d u c t (Q) N a_{2} S_{2} O_{3} + H_{2} O ? \to & (2) I_{2} N a H S O_{4} + o t h e r p r o d u c t (R) N_{2} H_{4} ? \to & (3) W a r m N_{2} + o t h e r p r o d u c t (S) X e F_{2} ? \to X e & (4) C l_{2} + o t h e r p r o d u c t \end{matrix}

Match the four starting meterials (P, Q, R, S) given in List – I with the corresponding reaction schemes
(I, II, III, IV) provided in List – II and select the correct answer using the code given below the lists.

Q. List-II gives distance between pair of points given in List-I, match them correctly.

\begin{matrix} L i s t - I & L i s t I I (P) & (- 5, 7), (- 1, 3) & (1) & 5 (Q) & (5, 6), (1, 3) & (2) & \sqrt{8} (R) & (\sqrt{3} + 1, 1), (0, \sqrt{3}) & (3) & \sqrt{6} (S) & (0, 0), (- \sqrt{3}, \sqrt{3}) & (4) & 4 \sqrt{2} \end{matrix}

List-II gives distance between pair of points given in List-I. Match them correctly.
$\begin{matrix} L i s t - I & L i s t I I (P) & (- 5, 7), (- 1, 3) & (1) & 5 (Q) & (5, 6), (1, 3) & (2) & \sqrt{8} (R) & (\sqrt{3} + 1, 1), (0, \sqrt{3}) & (3) & \sqrt{6} (S) & (0, 0), (- \sqrt{3}, \sqrt{3}) & (4) & 4 \sqrt{2} \end{matrix}$

List-II gives distance between pair of points given in List-I, match them correctly.
$\begin{matrix} L i s t - I & L i s t I I (P) & (- 5, 7), (- 1, 3) & (1) & 5 (Q) & (5, 6), (1, 3) & (2) & \sqrt{8} (R) & (\sqrt{3} + 1, 1), (0, \sqrt{3}) & (3) & \sqrt{6} (S) & (0, 0), (- \sqrt{3}, \sqrt{3}) & (4) & 4 \sqrt{2} \end{matrix}$

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The correct option is D P:3, Q:4, R:2, S:1(P) PbO2+H2SO4Δ−→PbSO4+O2+2H2O Other product = 2H2O ? = Δ (Q) Na2S2O3+5H2O4Cl2−−→2NaHSO4+8HCI Other product = 8 HCl ? = Cl2 (R) N2H4+2l2→N2+4HI ? = I2 (S) XeF2+NO→Xe+NOF Other Product = NOF ? = NO Hence answer is (D)