Question

The uncertainity in momentum of an electron is $1\times {10}^{-5}kg.m/s$. The uncertainity in its position will be ($h$ = $6.62\times {10}^{-34}kg.m/s$)

• A. $5.27\times {10}^{-30}m$
• B. $5.27\times {10}^{-28}m$
• C. $1.05\times {10}^{-28}m$
• D. $1.05\times {10}^{-26}m$

Answer 1

The correct option is A

$5.27\times {10}^{-30}m$

$\Delta x=\frac{h}{4\pi \Delta p}$

= $\frac{6.62\times {10}^{-34}}{4\times 3.14\times {10}^{-5}}$

= $5.27\times {10}^{-30}m$