Question

The uncertainity in the position of an electron (mass $9.1\times {10}^{-28}g$) moving with velocity of $3.0\times {10}^{4}c{m}^{-1}$ accurate up to 0.011%, will be

• A. 1.92 cm
• B. 7.68 cm
• C. 0.175 cm
• D. 3.84 cm

Answer 1

The correct option is C

0.175 cm

$\Delta x=\frac{h}{4\pi m\Delta v}$
= $\frac{6.625\times {10}^{-27}}{4\times 3.14\times 9.1\times {10}^{-28}\times 3.3}$

= $\frac{66.25}{4\times 3.14\times 9.1\times 3.3}$

= $0.175cm$