Question

The uncertainty in momentum of an electron is $1\times {10}^{-5}kg-m/s$. The uncertainty in its position will be ($h=6.62\times {10}^{-34}kg-m^2/s$)

• A. 1.05×10^-28 m
• B. 1.05×10^-26 m
• C. 5.27×10^-30 m
• D. 5.25×10^-28 m

Answer 1

The correct option is C

5.27×10^-30 m

According to $\Delta x\times \Delta p=\frac{h}{4\pi }$

$\Delta x=\frac{h}{\Delta p\times 4\pi }=\frac{6.62\times {10}^{-34}}{1\times {10}^{-5}\times 4\times 3.14}$

= $5.27\times {10}^{-30}m$