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Question

The uncertainty in the momentum of an eklectron is 10×105kgms1.The uncertainty in its position will be:

(h=6.62×1034kgm2s1)

A
1.05×1028
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B
1.05×1026
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C
5.27×1031
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D
5.25×1028
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Solution

The correct option is B 5.27×1031
Uncertainty in momentum ΔP=10×105kgms1
According to Heisenberg uncertainty principle
ΔPΔxh4z
10×105Δx6.626×10344×3.14
Δx6.626×10344×3.14×10×105
Δx0.5275×1030
Δx5.275×1031.

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