The uncertainty in the momentum of an electron is 1-0 - 10-5 kg ms - The uncertainty in the position will be A- 5-25 - 10-28 mB- 1-05 - 10-26 mC- 5-25 - 10-30 mD- 1-05 - 10-28

The correct option is C Δ x ×Δ p =h/4πΔ x =6.6 × 10^ 34/(4× 22/7 × 1 × 10^ 5)=5.25 × 10^ 30m ...

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Standard XII

Physics

Properties of Charges

The uncertain...

Question

The uncertainty in the momentum of an electron is $1.0 \times 10^{- 5}$ kg $m s^{-}$ . The uncertainty in the position will be

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Solution

The correct option is C
$Δ x \times Δ p = \frac{h}{4 π} Δ x = \frac{6.6 \times 10^{- 34}}{(\frac{4 \times 22}{7 \times 1 \times 10^{- 5}})} = 5.25 \times 10^{- 30} m$

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The uncertainty in the momentum of an electron is 1.0×10−5 kg ms−. The uncertainty in the position will be

The correct option is C Δx×Δp=h4πΔx=6.6×10−34(4×227×1×10−5)=5.25×10−30m

The uncertainty in the momentum of an electron is $1.0 \times 10^{- 5}$ kg $m s^{-}$ . The uncertainty in the position will be

The correct option is C
$Δ x \times Δ p = \frac{h}{4 π} Δ x = \frac{6.6 \times 10^{- 34}}{(\frac{4 \times 22}{7 \times 1 \times 10^{- 5}})} = 5.25 \times 10^{- 30} m$