Question

The uncertainty in the momentum of an electron is 1.0 $\times$ 10${}^{-5}$ kg m s${}^{-1}$. The uncertainty of its position will be:

[h = 6.626 $\times$ 10${}^{-34}$ kg m${}^2$ s${}^{-1}$]

• A. 1.05 $\times$ 10${}^{-28}$ m
• B. 1.05 $\times$ 10${}^{-26}$ m
• C. 5.27 $\times$ 10${}^{-30}$ m
• D. 5.25 $\times$ 10${}^{-28}$ m

Answer 1

The correct option is C 5.27 $\times$ 10${}^{-30}$ m

The uncertainty in the position of electron is

$\Delta x=\frac{h}{4\pi \Delta P}$

$=\frac{6.626\times {10}^{-34}}{4\times 3.1416\times 1.0\times {10}^{-5}}$

$=5.27\times {10}^{-30}m$.

Hence, the correct option is $C$