The unchanging relation between the weight of an object, its volume and density of the material it is made of is given by

w = d - v

No worries! We‘ve got your back. Try BYJU‘S free classes today!

v = d × w

No worries! We‘ve got your back. Try BYJU‘S free classes today!

w = d × v

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

v = d - w

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
w = d × v

Suggest Corrections

Similar questions

If the weight of an object is w, its volume is v and if it is made of a material of density d, then their relation can be written as

If volume of an utensil is $200 c m^{3}$ , then find its weight, given, density of the material it is made of is $7.56 g / c m^{3}$

If the volume of an utensil is $500 c m^{3}$ , then find its weight, given, the density of the material it is made of is $8.96 g / c m^{3}$

The weight of 1 cubic centimeter of iron is 7.8 grams. In what all ways can we express the relation between the weight of an object made of iron and its volume? Give a shortened version using letters.

Q. Relation between buoyant force and the volume of an object immersed in liquid is:

Given,

ρ_{l i q}

= Density of liquid

ρ_{o b j}

= Density of object

V_{t o t a l}

= Total volume of object

V_{s u b}

= Submerged volume of the object

Join BYJU'S Learning Program

The unchanging relation between the weight of an object, its volume and density of the material it is made of is given by

The correct option is C w = d × v

The correct option is C
w = d × v