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Radius of Gyration

The uniform d...

Question

The uniform disc shown in the figure has a moment of inertia of $0.6 k g m^{2}$ around the axis that passes through $O$ and is perpendicular to the plane of the page. If a segment is cut out from the disc as shown, the moment of inertia of the remaining disc is $\frac{1}{x} k g m^{2}$ . Find $x$ .

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Solution

$I = \frac{5}{6} I_{T o t a l} = \frac{5}{6} (0.6) k g . m^{2} = 0.5 k g . m^{2}$

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