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Question

The uniform disc shown in the figure has a moment of inertia of 0.6 kg-m2 around the axis that passes through O and is perpendicular to the plane. If a segment is cut out from the disc as shown, what is the moment of inertia of the remaining disc in kg-m2 ?

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Solution

Required moment of inertia is
I=12Mr212.mr2=56.12Mr2
(m=M/6), where m is the mass of the removed segment.
=56×0.6 kg-m2=0.5 kg-m2

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