The uniform plank of a see-saw is 8m long and is supported in the center. A boy weighing 50 kgf sits at a distance of 2.5 m from the fulcrum. Where must another boy weighing 40 kgf sit, so as to balance the plank?

Open in App

Solution

Given, Load = 50 kgf (first boy's weight)
Load arm = 2.5 m
Effort arm = x
another boy's weight be 40 kgf.

We know that

load×loadarm=effort×effortarm

50×2.5=x×40

x=50×2.540

x = 3.125 m

He should sit at a distance 3.125 from the centre

Suggest Corrections

Similar questions

A plank of a See-saw is 8m long and is supported at the centre. Rahul, who weighs 80 Kgf sits at a distance of 3 m from the fulcrum. Manish sits 4m from the fulcrum to balance the plank. What is Manish's weight

Q. The plank of a seesaw is

8 m

long and is supported at the centre. Neil, who weighs

80 kgf

sits at a distance of

3 m

from the fulcrum. John sits

4 m

from the fulcrum to balance the plank. What is John's weight?

When a boy weighing 20 kgf sits at one end of a 4 m long see-saw, it gets depressed at this end. How can it be brought to the horizontal position by a man weighing 40 kgf.

Q. A boy weighing

20 k g

is sitting at one end of a see-saw at a distance of

1.2 m

from the centre. Where should a man weighing

60 k g

sit on the see-saw, so that it stands balanced?

Q. A boy of mass 30 kg sitting at a distance of 2m from the middle of see-saw. Where should a boy of mass 40 kg sit so as to balance the see -saw?

Join BYJU'S Learning Program

The uniform plank of a see-saw is 8m long and is supported in the center. A boy weighing 50 kgf sits at a distance of 2.5 m from the fulcrum. Where must another boy weighing 40 kgf sit, so as to balance the plank?

Given, Load = 50 kgf (first boy's weight) Load arm = 2.5 m Effort arm = x another boy's weight be 40 kgf. We know that load×loadarm=effort×effortarm 50×2.5=x×40 x=50×2.540 x = 3.125 m He should sit at a distance 3.125 from the centre

Given, Load = 50 kgf (first boy's weight)
Load arm = 2.5 m
Effort arm = x
another boy's weight be 40 kgf.

We know that

load×loadarm=effort×effortarm

50×2.5=x×40

x=50×2.540

x = 3.125 m

He should sit at a distance 3.125 from the centre