Question

The unit cell of copper corresponds to a face centered cube of edge length 3.596 Å with one copper atom at each lattice point. The calculated density of copper in $kg/m^3$ is_____.

Answer 1

$a=3.596A^{\circ }$
$d=\frac{Z\times M}{N_A\times a^3}$
$d=\frac{4\times 63.54\times {10}^{-3}}{6.022\times {10}^{23}\times (3.596\times {10}^{-10}{)}^3}$
$d=\frac{254.16}{1000\times {10}^{23}\times {10}^{-30}\times 280.02}$
$d=9076.49{\text{kg/m}}^3$