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Byju's Answer
Standard XII
Chemistry
Relation Between r and a
The unit cell...
Question
The unit cell of nickel is a face-centered cube. The length of its side is
0.352
n
m
. Calculate the atomic radius of nickel.
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Solution
In FCC,
4
r
=
a
√
2
(along the face diagonal)
r
=
a
2
√
2
=
3.52
2
√
2
=
1.245
˚
A
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Similar questions
Q.
The unit cell of nickel is an fcc lattice. The length its side is 0.352 nm. Calculate the atomic radius of nickel.
Q.
The face-centered unit cell of nickel has an edge length of
352.39
p
m
. The density of nickel is
8.9
g
c
m
−
3
. Calculate the value of Avogadro's number. The atomic mass of nickel is
58.7
and
1
p
m
is equal to
10
−
10
c
m
.
Q.
Nickel crystallizes in a face-centered cubic structure, its density is
8.9
g cm
−
3
.
Calculate the radius (in
˚
A
) of the nickel atom.
[Given that the atomic weight of Ni is
58.89
amu.]
Q.
Nickel crystallizes in a face-centered cubic structure. If its density is
8.9
g cm
−
3
, then c
alculate the edge length (in
˚
A
) of the unit cell.
Q.
Gold (atomic radius
=
0.144
n
m
) crystallizes in a face centered unit cell. What is the length of a side of the unit cell?
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