Question

The unit of an electrical parameter whose formula is $\left[M^1{L}^2{T}^{-3}{A}^{-2}\right]$ is:

• A. ohm
• B. ampere
• C. volt
• D. newton

Answer 1

The correct option is A ohm

$V=IR$
So, $\left[R\right]=\left[\frac{V}{I}\right]$$=\left[\frac{W}{QI}\right]=\left[\frac{W}{I^{2}T}\right]=\left[\frac{F\times S}{I^2\times T}\right]=\left[\frac{m\times a\times S}{I^2\times T}\right]$$=\left[\frac{M\left(\frac{L}{T^2}\right)\times L}{A^2\times T}\right]$

$\Rightarrow \left[\Omega \right]=\left[M{L}^2{T}^{-3}{A}^{-2}\right]$