The unit of electric field intensity is:

Newton/ metre

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Coulomb/ newton

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Newton/ coulomb

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Joule/ newton

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Solution

The correct option is C Newton/ coulomb
Electric field due to a charge is given by $E = \frac{F}{q}$
Unit of force is Newton $(N)$ and that of charge is Coulomb $(C)$ .
So, unit of electric field is Newton/coulomb i.e $N / C$

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The unit of electric field intensity is:

The correct option is C Newton/ coulombElectric field due to a charge is given by E=FqUnit of force is Newton (N) and that of charge is Coulomb (C).So, unit of electric field is Newton/coulomb i.e N/C

The correct option is C Newton/ coulomb
Electric field due to a charge is given by $E = \frac{F}{q}$
Unit of force is Newton $(N)$ and that of charge is Coulomb $(C)$ .
So, unit of electric field is Newton/coulomb i.e $N / C$