The unit of rate constant for a given reaction is $M^{1 - n} L^{n - 1} t^{- 1}$ where n is order of reaction.

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
The statement is true. The unit of rate constant for a given reaction is $M^{1 - n} L^{n - 1} t^{- 1}$ where $n$ is order of reaction.It is generally form for expressing rate constant. Rates are usually given in concentrations units over time units. The units of the rate constants depend upon the order of the reaction. The concentration is molarity and time is in seconds.

Suggest Corrections

Similar questions

n^{t h}

K = 3 \times 10^{- 5} S^{- 1} a t m^{- 1}

L m o l^{- 1} s e c^{- 1} (T = 273.15 K)

n

k \times t = \frac{1}{n - 1} [\frac{1}{(a - x)^{n - 1}} - \frac{1}{a^{n - 1}}]

n

k = {[\frac{1}{C o n e}]}^{n - 1} \times T i m e^{- 1}

n

\frac{d x}{d t} = k [A]^{n}

l i t r e^{2} m o l^{- 2} t^{- 1}

t i m e^{- 1} ?

Join BYJU'S Learning Program