The unit of vander waals constant - a - is-correct answer -1- wrong answer -0-25 A- dm 6 atm mol -2B- dm 3 atm mol -2C- dm -6 atm mol -2D- dm 3 atm mol -1

The correct option is A dm^6 atm mol^ 2Vander Waals equation: (P + n^2aV^2)(V nb) =n RT unit of (P + n^2aV^2) is atm hence, unit of (n^2aV^2) is at ...

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Byju's Answer

Standard XII

Chemistry

Real Gases

The unit of v...

Question

The unit of vander waals constant $^{'} a^{'}$ is:
(correct answer +1, wrong answer -0.25)

d m^{6} a t m m o l^{- 2}

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d m^{3} a t m m o l^{- 2}

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d m^{- 6} a t m m o l^{- 2}

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d m^{3} a t m m o l^{- 1}

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Solution

The correct option is A $d m^{6} a t m m o l^{- 2}$
Vander Waals equation:
$(P + \frac{n^{2} a}{V^{2}}) (V - n b) = n R T$

$u n i t o f (P + \frac{n^{2} a}{V^{2}}) i s a t m$
$h e n c e, u n i t o f (\frac{n^{2} a}{V^{2}}) i s a t m$

$\Rightarrow$
$\frac{m o l^{2} a}{L^{2}} = a t m$
$u n i t o f a = L^{2} a t m m o l^{- 2} = d m^{6} a t m m o l^{- 2}$

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Similar questions

Q. Calculate the critical constants of a gas whose vander Waals' constants are

a = 0.715 L^{2}

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and

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Q. Consider the following table:

Gas	$a (k P a d m^{6} m o l^{- 2})$	$b (d m^{3} m o l^{- 1})$
A	642.32	0.05196
B	155.21	0.04136
C	431.91	0.05196
D	155.21	0.4382

a and b are vander waals constant. The correct statement about the gases is:

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Q. Calculate the pressure of 15 mol neon at

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The unit of vander waals constant ′a′ is: (correct answer +1, wrong answer -0.25)

The correct option is A dm6 atm mol−2Vander Waals equation: (P+n2aV2)(V−nb)=nRT unit of (P+n2aV2) is atm hence, unit of (n2aV2) is atm ⇒ mol2aL2=atm unit of a=L2atm mol−2=dm6 atm mol−2

The unit of vander waals constant $^{'} a^{'}$ is:
(correct answer +1, wrong answer -0.25)