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Question

The unit vector along ^i+^j is:

A
^k
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B
^i+^j
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C
^i+^j2
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D
^i+^j2
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Solution

The correct option is C ^i+^j2
Unit vector along(i+j)is(i+j)|i+j|
|i+j| is magnitude of(i+j)
we know,
i and j are perpendicular to each other
So, |i+j|=i2+j2+2ijcos90o
1+1=2
hence, unit vector along (i+j)is(i+j)2

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